Thank you. It's great to feel welcome.
The technical side of synthesizers isn't difficult to grasp if broken down into easily digestible chunks. I began DIY-ing audio circuits in the late 60s-early 70s even before I knew what a proper synthesizer was. When I discovered Moog synthesizers in 71 I began reading every book on electronics, synthesis and sound theory that I could get my hands on. By 1973 (at the ripe old age of 16) I'd designed and built my own synthesizer, which included: 2 VCOs, a "modulation VCO", what I called a cascade VCF w/ switchable attack, release or attack, decay EG, a VCA w/attack, release EG, and (wait for it) a programmable arpeggiator! I played it using a keyboard I'd salvaged from an old home organ I bought from someone for $30.00 USD. I dearly regret not having saved that little creation of mine, but being young and having a budget of $0.00 it was eventually cannibalized for other projects. *sigh*
Anyway...
A little more on ancient VCO technology.
IMHO, if there's any one component to blame for having caused so much design stress it's the charging capacitor. If, for example, you were to build a simple UJT oscillator like the one I described earlier (called a relaxation oscillator, BTW) and charged the capacitor with a voltage, the resulting wave would not be a perfect sawtooth. When a capacitor is charged with a voltage it charges exponentially, so instead of a nice straight ramp leading up to the peak you get a funny "humped" sort of shape. To give you an idea, imagine a sign wave beginning it's upward swing, then before it reaches the crest it's suddenly chopped. This type of wave form, though having an interesting mellow timbre, sounds nothing like a true sawtooth wave.
The solution to this is to charge the capacitor with a current, rather than a voltage. When a current is used the capacitor produces a nice straight ramp as it charges. The easiest way to convert a voltage into a current is to use a transistor. Applying a voltage to a properly biased transistor will produce a current at it's output (this circuit is known as a current source or current sink, depending on it's configuration).
There you go! A perfect sawtooth!
[A tidbit; the core of most if not all discrete analog oscillators are actually Current Controlled Oscillators. However, if one considers the voltage/current converter and wave shaping components as part of a single circuit, then "VCO" really isn't much of a misnomer.]
Now, however, the domino effect begins. A single transistor is far too unstable on it's own, so a second transistor can be added to produce a much more precise current. Connecting two matching NPN transistor into what is called a Darlington pair creates an excellent current source for our VCO example.
http://en.wikipedia.org/wiki/Darlington_transistorSo far, so good. In fact, an op-amp can be added to the circuit to increase precision even further.
The only problem is, at this stage the VCO is linear response. In other words, a change of one volt at the input will not produce a one octave change of output frequency. It's a shame too, because this is a very stable design.
What we need to get the 1V/Oct change is the dreaded linear-voltage-to-exponential-current converter...
...which I'll go into in my next post.
As always, feel free to point out any mistakes I may have made.
Cheers!